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Rescue Helicopter

Help! A rescue helicopter drops a box of supplies from a height of 160 feet ...?

A rescue helicopter drops a box of supplies from a height of 160 feet. After t seconds, the box is 160 - 16t ^ 2 feet above the ground. a) Find the velcocity of the fund at time t = 1 b) With what speed does the strike fund in the field?

The velocity v is d / t, where d is the distance (in this case the height). If the fund is 160 - 16t ^ 2 feet above the ground, he fell d = 160 - (160 - 16t ^ 2) feet at time t. (Remember the case of starting point is 160 feet above the ground, instead of 0 feet above the ground!) a) Now, substitute this value in v = d / t to obtain the velocity at t = 1. b) How long cash pass down to how many seconds before it hits the ground? Must be 160 - (160 - 16t ^ 2) = 0. Solve t, you know how long the fund has dropped, now put that response at v = d / t